10x^2-20x-36=0

Solution for 10x^2-20x-36=0 equation:

10x^2-20x-36=0

a = 10; b = -20; c = -36;
Δ = b2-4ac
Δ = -202-4·10·(-36)
Δ = 1840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1840}=\sqrt{16*115}=\sqrt{16}*\sqrt{115}=4\sqrt{115}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{115}}{2*10}=\frac{20-4\sqrt{115}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{115}}{2*10}=\frac{20+4\sqrt{115}}{20}
$